2w^2=1800

Solution for 2w^2=1800 equation:

2w^2=1800

We move all terms to the left:

2w^2-(1800)=0

a = 2; b = 0; c = -1800;
Δ = b2-4ac
Δ = 02-4·2·(-1800)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*2}=\frac{-120}{4}
=-30
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*2}=\frac{120}{4}
=30
$